2x^2+300x-11250=0

Solution for 2x^2+300x-11250=0 equation:

2x^2+300x-11250=0

a = 2; b = 300; c = -11250;
Δ = b2-4ac
Δ = 3002-4·2·(-11250)
Δ = 180000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{180000}=\sqrt{90000*2}=\sqrt{90000}*\sqrt{2}=300\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-300\sqrt{2}}{2*2}=\frac{-300-300\sqrt{2}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+300\sqrt{2}}{2*2}=\frac{-300+300\sqrt{2}}{4}
$